Question on: WAEC Physics - 2016
The distance between two successive trough of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave
A
165.0 ms-1
B
330.0ms-1
C
41.5ms-1
D
85.0ms-1
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Correct Option: B
v = f(\lambda)
= 825 x 0.4
= 330.0ms-1
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